6(2x^2)=12

Solution for 6(2x^2)=12 equation:

6(2x^2)=12

We move all terms to the left:

6(2x^2)-(12)=0

a = 62; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·62·(-12)
Δ = 2976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2976}=\sqrt{16*186}=\sqrt{16}*\sqrt{186}=4\sqrt{186}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{186}}{2*62}=\frac{0-4\sqrt{186}}{124}
=-\frac{4\sqrt{186}}{124}
=-\frac{\sqrt{186}}{31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{186}}{2*62}=\frac{0+4\sqrt{186}}{124}
=\frac{4\sqrt{186}}{124}
=\frac{\sqrt{186}}{31}
$